22-17x+3x^2=0

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Solution for 22-17x+3x^2=0 equation: 



22-17x+3x^2=0

a = 3; b = -17; c = +22;
Δ = b2-4ac
Δ = -172-4·3·22
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-5}{2*3}=\frac{12}{6}
=2
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+5}{2*3}=\frac{22}{6}
=3+2/3
$

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